-2x^2-16x+936=0

Solution for -2x^2-16x+936=0 equation:

-2x^2-16x+936=0

a = -2; b = -16; c = +936;
Δ = b2-4ac
Δ = -162-4·(-2)·936
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-88}{2*-2}=\frac{-72}{-4}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+88}{2*-2}=\frac{104}{-4}
=-26
$